! Program to test the MINLOC and MAXLOC intrinsics program testmmloc implicit none integer, dimension (3, 3) :: a integer, dimension (3) :: b logical, dimension (3, 3) :: m, tr integer i character(len=10) line a = reshape ((/1, 2, 3, 5, 4, 6, 9, 8, 7/), (/3, 3/)); tr = .true. b = minloc (a, 1) if (b(1) .ne. 1) STOP 1 if (b(2) .ne. 2) STOP 2 if (b(3) .ne. 3) STOP 3 b = -1 write (line, 9000) minloc(a,1) read (line, 9000) b if (b(1) .ne. 1) STOP 4 if (b(2) .ne. 2) STOP 5 if (b(3) .ne. 3) STOP 6 m = .true. m(1, 1) = .false. m(1, 2) = .false. b = minloc (a, 1, m) if (b(1) .ne. 2) STOP 7 if (b(2) .ne. 2) STOP 8 if (b(3) .ne. 3) STOP 9 b = minloc (a, 1, m .and. tr) if (b(1) .ne. 2) STOP 10 if (b(2) .ne. 2) STOP 11 if (b(3) .ne. 3) STOP 12 b = -1 write (line, 9000) minloc(a, 1, m) read (line, 9000) b if (b(1) .ne. 2) STOP 13 if (b(2) .ne. 2) STOP 14 if (b(3) .ne. 3) STOP 15 b(1:2) = minloc(a) if (b(1) .ne. 1) STOP 16 if (b(2) .ne. 1) STOP 17 b = -1 write (line, 9000) minloc(a) read (line, 9000) b if (b(1) .ne. 1) STOP 18 if (b(2) .ne. 1) STOP 19 if (b(3) .ne. 0) STOP 20 b(1:2) = minloc(a, mask=m) if (b(1) .ne. 2) STOP 21 if (b(2) .ne. 1) STOP 22 b(1:2) = minloc(a, mask=m .and. tr) if (b(1) .ne. 2) STOP 23 if (b(2) .ne. 1) STOP 24 b = -1 write (line, 9000) minloc(a, mask=m) read (line, 9000) b if (b(1) .ne. 2) STOP 25 if (b(2) .ne. 1) STOP 26 if (b(3) .ne. 0) STOP 27 b = maxloc (a, 1) if (b(1) .ne. 3) STOP 28 if (b(2) .ne. 3) STOP 29 if (b(3) .ne. 1) STOP 30 b = -1 write (line, 9000) maxloc(a, 1) read (line, 9000) b if (b(1) .ne. 3) STOP 31 if (b(2) .ne. 3) STOP 32 if (b(3) .ne. 1) STOP 33 m = .true. m(1, 2) = .false. m(1, 3) = .false. b = maxloc (a, 1, m) if (b(1) .ne. 3) STOP 34 if (b(2) .ne. 3) STOP 35 if (b(3) .ne. 2) STOP 36 b = maxloc (a, 1, m .and. tr) if (b(1) .ne. 3) STOP 37 if (b(2) .ne. 3) STOP 38 if (b(3) .ne. 2) STOP 39 b = -1 write (line, 9000) maxloc(a, 1, m) read (line, 9000) b if (b(1) .ne. 3) STOP 40 if (b(2) .ne. 3) STOP 41 if (b(3) .ne. 2) STOP 42 b(1:2) = maxloc(a) if (b(1) .ne. 1) STOP 43 if (b(2) .ne. 3) STOP 44 b = -1 write (line, 9000) maxloc(a) read (line, 9000) b if (b(1) .ne. 1) STOP 45 if (b(2) .ne. 3) STOP 46 b(1:2) = maxloc(a, mask=m) if (b(1) .ne. 2) STOP 47 if (b(2) .ne. 3) STOP 48 b(1:2) = maxloc(a, mask=m .and. tr) if (b(1) .ne. 2) STOP 49 if (b(2) .ne. 3) STOP 50 b = -1 write (line, 9000) maxloc(a, mask=m) read (line, 9000) b if (b(1) .ne. 2) STOP 51 if (b(2) .ne. 3) STOP 52 if (b(3) .ne. 0) STOP 53 9000 format (3I3) end program